V 1 = ρ 2 p (so that the term 2 g h can be neglected), P = P o v 1 = 2 g h Applying Bernoulli's equation to points 1 and 2 and noting that at the hole P 1 is equal to atmospheric pressure P 0 , we find that P 0 + 2 1 ρ v 1 2 + ρ g y 1 = P + ρ g y 2 Determine the speed of the liquid as it leaves the hole when the liquid's level is a distance h above the hole.Ī 2 > A 1 , the liquid is approximately at rest at the top of the tank, where the pressure is P. The air above the liquid is maintained at a pressure P. Please use at your own risk and verify critical calculations independently.Torricelli's law is a theorem in fluid dynamics relating the speed of fluid flowing out of an opening to the height of fluid above the opening.Īn enclosed tank containing a liquid of density ρ has a hole in its side at a distance y 1 from the tank's bottom (Fig.) The hole is open to the atmosphere, and its diameter is much smaller than the diameter of the tank. We have made every effort to ensure the accuracy of the information presented above, however Strain Measurement Devices assumes no liability for damages resulting from the use of this resource. This calculator is provided for reference only. G is the acceleration due to gravity (typically 9.80665m s^(-2)) SG is the specific gravity of the liquid being measured Ρ0 is the density of water (1000kg m^(-3) ) If the vessel is not vented, then it is necessary to account for the actual pressure above the liquid. This calculation assumes that the top of the fluid column is vented to atmosphere. The output of this calculator is the height difference between the top of the liquid and the location of the pressure measurement.
This calculator can be used to calculate the level of a liquid in a tank when the hydrostatic pressure in the tank and the specific gravity of a liquid are known.
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